Question

The actual population of the U.S. (as of 2012) is approximately 3.14 x 10°. How does the population density ofCalifornia (i.e., the number of people per square mile) compare with the population density of the U.S.?

Answer 1

We have the folllowing, the density population in US is:

`d=(population)/(area)=(3.14\cdot10^8)/(3.794\cdot10^6)=82.76\text{ }`

The density population in California is:

`d=(population)/(area)=(3.804\cdot10^7)/(1.637\cdot10^5)=232.37`

The density in Califoria is 232.37 per mi^2

therefore, the density in California is higher than in the US.