To find how much interest is earned after 6 years, we apply the following formula:
![\text{Interest}=P(1+(r)/(100n))^(tn)-P](https://img.qammunity.org/2023/formulas/mathematics/college/27i7a24cyvohfdyivgzdoej47isexleldl.png)
where:
- P = amount initially invested = $20,000
- r = percentage rate at which the amount was invested = 4.5
- t = the duration for which the investment was made = 6 years
- n = the frequency at which the interest is compounded = quarterly = 4
Now, we simply substitute the values into the formula to obtain the Interest, as follows:
![\begin{gathered} \text{Interest}=P(1+(r)/(100n))^(tn)-P \\ \Rightarrow\text{Interest}=20000(1+(4.5)/(100(4)))^(6*4)-20000 \\ \Rightarrow\text{Interest}=20000(1+(4.5)/(400))^(24)-20000 \\ \Rightarrow\text{Interest}=20000(1+0.01125)^(24)-20000 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/z17a6cb7qr1oe5hhxi4e605570n0tpqnev.png)
![\Rightarrow\text{Interest}=20000(1.01125)^(24)-20000](https://img.qammunity.org/2023/formulas/mathematics/college/aht3cnvof1q541wsabygpo37hdyp1hzt46.png)
![\begin{gathered} \Rightarrow\text{Interest}=20000*1.3080-20000 \\ \Rightarrow\text{Interest}=26160-20000 \\ \Rightarrow\text{Interest}=6160\text{ dollars} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7pqjscg7eg6qvo8llutoigcek8juubf6ys.png)
Therefore, the interest earned after 6 years is: $6,160