Question

The equation for the line that has a slope of and passes through (0, 10) is co - 3x + 10 3 g2 y = 10x 13 3 8 :: y = - 10

Answer 1

`\begin{gathered} \text{slope = m = -}(3)/(8) \\ u\sin g\text{ the slope form equation} \\ m=(y-y_1)/(x-x_1) \\ m=(y-10)/(x-0) \\ m=(y-10)/(x) \\ mx=y-10 \\ y=mx+10 \\ y=-(3)/(8)x+10 \end{gathered}`