Answer:
• 14 and 16
,
• -16 and -14.
Step-by-step explanation:
Let the smaller of the two consecutive even integers = x
The larger of the two consecutive even integers = x+2
We are told that their product is 224, therefore:
![\begin{gathered} x(x+2)=224 \\ x^2+2x=224 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/acxw8dotvy8qktl0oaoeef3dwdg2dlhg30.png)
We solve the resulting quadratic equation for x.
![\begin{gathered} x^2+2x-224=0 \\ x^2+16x-14x-224=0 \\ x(x+16)-14(x+16)=0 \\ (x-14)(x+16)=0 \\ x-14=0\text{ or }x+16=0 \\ x=14\text{ or x=-16} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/c8we7hd9tq5a7i1jwxjhkwbuspopvwqv9q.png)
Therefore, the two consecutive even integers are:
• 14 and 16
,
• -16 and -14.
,
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