Question

Line e passes through points (-51, -28) and (-10, 14). Line fis perpendicular to e. What is theslope of line f?

Answer 1

`\begin{gathered} (-51,\text{ -28) and (-10, 14)} \\ \text{slope for e}(M1)\text{: }\frac{y2-\text{ y1}}{x2\text{ -x1}} \\ \text{slope= }(14--28)/(-10--51)\text{ = }(42)/(41) \\ \text{for perpendicular: means M1}* M2\text{ = -1} \\ \text{ }(42)/(41)*\text{ M2 = -1} \\ \text{ 42M1 = -41 } \\ \text{ M1 = }(-41)/(42) \end{gathered}`