Question

You need to fence a triangular lot. If the two sides measure 84 feet and 78 feet and

the angle between the two sides is 105°, what is the amount of fencing needed to
enclose the third side? Round to the nearest tenth of a foot.
Please help?

Answer 1

A tiny cat named Tiny sits all day in the window and watches people pass by.

Explanation:

A tiny cat named Tiny sits all day in the window and watches people pass by.A tiny cat named Tiny sits all day in the window and watches people pass by.A tiny cat named Tiny sits all day in the window and watches people pass by.A tiny cat named Tiny sits all day in the window and watches people pass by.A tiny cat named Tiny sits all day in the window and watches people pass by.A tiny cat named Tiny sits all day in the window and watches people pass by.A tiny cat named Tiny sits all day in the window and watches people pass by.

Answer 2

The length of the third side of the fence is 128.6 feets.

Since we are given two sides and an included angle, we use the cosine rule ;

• a² = b² + c² - 2bc * CosA

Here, a = amount of fencing needed to enclose the third side ;

a² = 84² + 78² - 2(84*78) * cos(105)

a² = 13140 - 13104(cos(105))

a² = 13140 - (-3391.565)

a² = 16531.565

a = √16531.565

a = 128.575

Hence, the length of the third side to the nearest tenth of a foot is 128.6 feets.