Question

I tried this question and most of my answers I got were different from the memo in the text book

Answer 1

F2 = 2.152 N

Step-by-step explanation

Since the fluid is all the same, the pressure on each disk is the same:

`P_1=P_2`

Knowing that

`P=(F)/(A)`

We get the formula

`(F_1)/(A_1)=(F_2)/(A_2)`

We have to solve for F2:

`F_2=F_1(A_2)/(A_1)`

It is given that F1 = 0.385N, A1 = 10.512m² and A2 = 58.755m². The force on the larger part is:

`F_2=0.385N\cdot(58.755m^2)/(10.512m^2)`
`F_2\approx2.152N`