Answer:
![2.64\text{ seconds}](https://img.qammunity.org/2023/formulas/mathematics/college/95zhom7y15xzqq6iimt6j99mxb17f00ifd.png)
Step-by-step explanation:
Here, we want to calculate the number of minutes it takes the ball to hit the ground
To calculate this, we have to solve the quadratic equation and record the positive t value (this is because time t, cannot be negative)
Mathematically, we have the equation to use as follows:
![t\text{ = }(-b\pm√(b^2-4ac))/(2a)](https://img.qammunity.org/2023/formulas/mathematics/college/r1pqe73ywph506yhrs3xbko5rpepnuyft8.png)
where a is the coefficient of t^2 which is -16
b is the coefficient of t which is -15
c is the last number which is 151
Substituting the values, we have it that:
![t\text{ = }\frac{15\pm\sqrt{(-15)\placeholder{⬚}^2-4(-16)(151)}}{2(-16)}](https://img.qammunity.org/2023/formulas/mathematics/college/8nx1yrf23jxec5wdwp20boxoyzehbrh9wt.png)
![\begin{gathered} t\text{ = }(15\pm√(9889))/(-32)\text{ = }(15\pm99.44)/(-32) \\ \\ t\text{ = }(15+99.44)/(-32)\text{ or }(15-99.44)/(-32) \\ \\ t\text{ = -3.58 or 2.64} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/49jh56acu2hsc1fmubxfk1bs5q4v7n0i1u.png)
Since t cannot be negative, we have t as 2.64 seconds