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Find the value of x. Round tothe nearest tenth.27°X34°11X == [?]Law of Sines: sin Asin Bb=sin CaС

Find the value of x. Round tothe nearest tenth.27°X34°11X == [?]Law of Sines: sin-example-1

1 Answer

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In the given triangle ABC,

Using sine rule


(\sin A)/(a)\text{ = }(\sin B)/(b)=\text{ }(\sin C)/(c)

Therefore,


\begin{gathered} (\sin27)/(11)\text{ = }(\sin34)/(x)=(\sin B)/(c) \\ (\sin27)/(11)\text{ = }(\sin34)/(x) \end{gathered}

Cross multiplying on both the sides,


\begin{gathered} \sin \text{ 27 }*\text{ x = sin34 }*\text{ 11} \\ x\text{ = }\frac{\text{sin34 }*\text{ 11}}{\sin\text{ 27}} \\ x\text{ = 13.549} \\ x\text{ }\approx13.55 \end{gathered}

Thus the value of x is 13.55 .

Find the value of x. Round tothe nearest tenth.27°X34°11X == [?]Law of Sines: sin-example-1
User Ivan Bilan
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