To determine the slope of a line that is perpendicular to the line with equation
![0.5x-5y=9](https://img.qammunity.org/2023/formulas/mathematics/college/6b474727twtsmmiplrhmvgyhqmd0fysonf.png)
![\begin{gathered} 0.5x-5y=9 \\ 0.5x-9=5y \\ 5y=0.5x-9 \\ \text{divide through by 5} \\ (5y)/(5)=(0.5x)/(5)-(9)/(5) \\ y=0.1x-(9)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9ub5cgz0ft4y36m0fo9waxpbfffthixq3r.png)
The equation of a straight line is y =mx+c
![\begin{gathered} y=mx+c \\ \text{compare with } \\ y=0.1x-(9)/(5) \\ m_1=\text{ 0.1} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/440nmaqdx9q03ptm8ikkwbzgq7kzh4gvav.png)
Two lines are perpendicular if m1. m2 = -1 Another way of saying this is the slopes of the two lines must be negative reciprocals of each other.
![\begin{gathered} m_1.m_2\text{ = -1} \\ 0.1m_2\text{ = -1} \\ m_2\text{ = }(-1)/(0.1) \\ m_2\text{ = -10} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rtaxk9je9qld4hqp64vl15mbv4ojuxdy4p.png)
Hence the slope of the line that is perpendicular to a line = -10
Hence the correct answer is Option A