Question

Can you just show the ans I done need to see working

Answer 1

Let

m1= 10 kg

m2= 6 kg

Distance of m2 from pivot = 4 m

Distance of m1 from pivot = x

Procedure

If system is not rotating then it should be in equilibrrium position.

`\begin{gathered} m_1g_{}x=m_2gd_2 \\ x=(m_2d_2)/(m_1) \\ x=(6kg\cdot4m)/(10kg) \\ x=2.4m \end{gathered}`

the 10 kg mass is 2.4m away from the pivot