Question

Solve quadratic equations problemill send a picture of the question

Answer 1

The given equation is

1)

`4x^2+20x+24=0^{}_{}`

Divide by 4, we get

`x^2+5x+6=0^{}_{}`

`x^2+3x+2x+6=0^{}_{}`
`x(x^{}+3)+2(x+3)=0^{}_{}`
`(x+3)(x+2)=0`

By factoring in this equation. we can find a solution

Hence here the answer is

Factor the equation

2)

The given equation is

`3x^2+30x=24`

Divide by 3, we get

`x^2+10x=8`

`x^2+10x-8=0`

`x^2+10x+25-25-8=0`

`(x-5)^2-33=0`
`(x-5)^2=33`

`x-5=\pm\sqrt[]{33}`

`x=\pm\sqrt[]{33}+5`

Hence we solved by using completing the square.

For this answer is

Complete the square.

3)

The given equation is

`x^2+5x+2=0`

We are not able to factor this equation.

We need to use the quadratic formula to solve this quadratic equation.

Fo this the answer is

Use the quadratic formula