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7 cm7(Score for Question 3: __ of 4 points)3. A) Find the probability that a point chosen randomly inside the rectangle willbe in the triangle. Show all calculations. Round answer to the nearesthundredth.3 cmAnswer:4 cm5 cm2 cm2 cmB) Find the probability that a point chosen randomly inside the rectangle willbe in the shaded region. Show all calculations. Round answer to the nearest hundredth.Answer:

7 cm7(Score for Question 3: __ of 4 points)3. A) Find the probability that a point-example-1
User Ian Renton
by
4.3k points

1 Answer

5 votes

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

Diagram

Step 02:

a.

Big Rectangle Area = s²

= 7 cm * 5 cm

= 35 cm²

Triangle Area = (b * h) / 2

= (3 cm * 4 cm) / 2

= 12 cm² / 2 = 6 cm²

probability = Triangle Area / Big Rectangle Area

= 6 cm² / 35 cm² = 6 / 35 = 0.171

b.

Small Rectangle Area = s²

= 2 cm * 2 cm

= 4 cm²

Shaded region Area = Big Rectangle Area - Triangle Area - Small Rectangle Area

Shaded region Area = 35 cm² - 6 cm² - 4 cm² = 25 cm²

probability = Shaded region Area / Big Rectangle Area

= 25 cm² / 35 cm² = 25 / 35 = 5 / 7 = 0.714

The answer is:

a. probability = 6 / 35 = 0.171

b. probability = 5 / 7 = 0.714

User John Tate
by
4.3k points