Question

Multiple choice triangle. im pretty sure its pythagorean theorem but please let me know

Answer 1

To solve this triangle, we cannot use either the Pythagorean Theorem or the Law of Cosines. We need more information.

Conversely, we can use SOHCAHTOA, in the sense that we can use the SOH part of this (Sine = opposite side over hypotenuse), that is, we can use angle 33 as the reference angle, and we have a right triangle here. Then, using trigonometric ratios, we can use:

`\sin (\theta)=(opp)/(hyp)\Rightarrow\sin (33)=(x)/(29)\Rightarrow x=29\cdot\sin (33)\Rightarrow x=15.7945`

We also can use the Law of Sines to solve it:

`(x)/(\sin(33))=(29)/(\sin(90))\Rightarrow(x)/(\sin(33))=(29)/(1)\Rightarrow x=29\cdot\sin (33)\Rightarrow x=15.7945`

Therefore, we can solve this triangle using both Law of Sines and SOHCAHTOA. (We can select two options: c and d.)