Question

Hello I need help please.The choices for f(-6): A. f(-6) ; B. The answer is not a real number

Answer 1

Given the function:

`f\mleft(x\mright)=√(x-1)`

First part:

You need to substitute the following value of "x" into the function:

`x=1`

In order to find:

`f(1)`

Then, substituting and evaluating, you get:

`\begin{gathered} f(1)=\sqrt[]{1-1} \\ f(1)=\sqrt[]{0} \\ f(1)=0 \end{gathered}`

Second part:

Substitute this value of "x" into the function:

`x=-6`

And then evaluate, in order to find:

`f(-6)`

You get:

`\begin{gathered} f(-6)=\sqrt[]{-6-1} \\ f(-6)=\sqrt[]{-7} \end{gathered}`

Since the Radicand is negative, it is not a Real Number.

Therefore, the answers are:

First part:

A.

`f(1)=0`

Second part:

B. The answer is not a real number.