Question

I just need the properties in order help plz

Answer 1

`\sf \longmapsto6(x−5)=3x−12`

• Simplify both sides

`\sf \longmapsto(6)(x)+(6)(−5)=3x+−12`

`\sf \longmapsto6x+−30=3x+−12`

`\sf \longmapsto \: 6x - 30 = 3x - 12`

• Subtract 3x from both sides

`\sf \longmapsto \: 6x−30−3x=3x−12−3x`

`\sf \longmapsto3x−30=−12`

• Add 30 to both sides

`\sf \longmapsto3x−30+30=−12+30`

`\sf \longmapsto3x=18`

• Divide both sides by 3

`\sf \longmapsto \: (3x)/(3) = (18)/(3)`

`\sf \longmapsto \: x = 6`

`\boxed{\sf \: x = 6 }`

Answer 2

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`6x - 30 - 3x = - 12`

• move the variable to the left hand side and change its sign, move the constant to the right hand side and change its sign

`6x - 30 = - 12`

• collect like terms and calculate the sum

`3x = - 18`

• divide both sides of the equation by 3

`x = 3`

hope it helps

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