Given:
![2√(x-5)=2](https://img.qammunity.org/2023/formulas/mathematics/college/r126xcx9g0s54s2s6m8ldcnknznxe9xxm5.png)
Required:
We need to solve for x and identify if it is an extraneous solution.
Step-by-step explanation:
First find the value of x
![\begin{gathered} 2√(x-5)=2 \\ √(x-5)=1 \\ x-5=1 \\ x=6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ha34jx5uvvp6sczsldl3cs8pa614wun7zs.png)
This solution is not extraneous, because extraneous solution emerage from solving the problem but are not actually valid solution fro initial problem.
With rounding , this solution is valid for the initial problem
Final answer:
A