Answer:
50%
Step-by-step explanation:
To solve this, we'd need to use a Punnett square. Since the mother has a heterozygous genotype and has an A-blood phenotype, we know that she is AO and the father is AB.
A B
A AA AB
O AO BO
According to this, the four possible blood types, with equal probability are: AA, AB, AO, and BO. Both AA and AO genes will result in type-A blood, since A is dominant over O. Therefore, there is a 2 in 4 (or 1 in 2, or 50%) chance of the child having type-A blood.