Question

Solve the Quadratic

Solve for x.

x^2- x=20

Solution 1:
Solution 2:

Answer 1

Solution 1:
`x = 5`

Solution 2:
`x = -4`

Explanation:

The first is organize the given equation to the next form

`ax^2 + bx + c`

So you substract -20 in both sides of the equation

`x^2 - x - 20 = 0`

Know you can use the quadratic formula or find two number that sum give us
`b` and multiplied
`c`.

`b = s + r\\c = sr`

Replacing with the given values we have:

`-1 = s + r\\-20 = sr`

With a trial and error the numbers are -5 and 4. Then you change the equation to

`x^2 - x - 20 = (x - 5)(x + 4)`

And the equation is equal to 0 when
`x` is equal to 5 and -4.

Answer 2

solution 1: 5

solution 2: -4

Explanation:

x²-x-20=0;

(x-5)(x+4)=0;

x₁=5; x₂=-4.