Question

Solve the Quadratic

Solve for x. Write in simplified radical form.

2x^2 + 3x – 20 = 0

Solution 1:
Solution 2:

Answer 1

`2x^2 +3x -20 =0\\\\\\\implies x = (-3 \pm √((-3)^2 - 4 \cdot 2 \cdot (-20)))/(2 \cdot 2)\\\\\\\implies x = (-3 \pm √(169))/(4)\\\\\\\implies x = \frac{-3\pm 13} 4 \\\\\\\text{Hence} \\\\x = (-3+ 13)/(4) = \frac{10} 4 = \frac{5}2\\\\\text{Or}\\\\x= \frac{-3-13}4 = -\frac{16}4 =-4`

Answer 2

~quadratic equation

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2x² + 3x - 20 = 0

= a + b = 3

= ab = 2(-20) = -40

= a = -5

= b = 8

= (2x² - 5x) + (8x - 20)

= x(2x - 5) + 4(2x - 5)

= (2x - 5) (x + 4)

= Solution 1 : x = 5/2 ✔️

Solution 2 : x = -4 ✔️

~ nice to help you ^^