We are given the following expression
![a^(3)-5g+\sqrt[]{34-30}+\frac{\sqrt[]{g+1}}{2}](https://img.qammunity.org/2023/formulas/mathematics/college/f2ibes9a4spc0mztabfw56kqn1q8vis0l1.png)
whenever a=2 and g=3. What we should do, is replace the values of a and g and then operate accordingly. We will do this expression by expression and then operate eache term.
Consider the term a³. If a=2, then

in the case for 5g, if g=3, then

Now, let us analize sqrt(g+1), if g=3, then g+1=4. Then
![\frac{\sqrt[]{g+1}}{2}=\frac{\sqrt[]{4}}{2}](https://img.qammunity.org/2023/formulas/mathematics/college/emc4g6vcvegcj0awpxqzq7ehz5yhwilkon.png)
in this case, we will always use positive square roots, so
![\frac{\sqrt[]{g+1}}{2}=\frac{\sqrt[]{4}}{2}=(2)/(2)=1](https://img.qammunity.org/2023/formulas/mathematics/college/lycbr3v9imrvkmj2wzj8rza9pg0w2lud9l.png)
Finally, we will calculate the remaining term
![\sqrt[]{34-30}=\sqrt[]{4}=2](https://img.qammunity.org/2023/formulas/mathematics/college/szzuf45wcnhxrql67bfa723e6lng912eca.png)
Then, the final procedure would be

So the final answer is -4