60,621 views
26 votes
26 votes
Here is another one if anyone can help me out

Here is another one if anyone can help me out-example-1
User Khilen Maniyar
by
2.7k points

1 Answer

19 votes
19 votes

Answer:

1. 3 × Equation [A2] --> Equation [B2]

2. 4 × Equation [B1] + Equation [B2] --> Equation [C2]

Explanation:

1. 3 × Equation [A2] --> Equation [B2]

Technically 1 x equation [A1] --> equation [B2] works, but I doubt you're meant to do that lol

Instead, this works:

4x × 3 = 12x

-7y × 3 = -21y

8 × 3 = 24

2. 4 × Equation [B1] + Equation [B2] --> Equation [C2]

(-3x × 4) + 12x = -12x + 12x = 0x

(2y × 4) + -21y = 8y - 21y = -13y

(7 × 4) + 28 = 28 + 24 = 52

=========================

I'll try to explain my process a little this time.

From A to B, you can see that equation 2 changed. Looking at the first term, 4x changed to 12x. Thats a multiplier of 3, and you can check that on the rest. In this case, that works.

Then from B to C, equation 2 changed again. This time, I noticed that x was canceled out. That means -12x had to have been added to 12x. In equation 1, theres a -3x. 4 times that is -12, and adding -12x to equation 2 works. Check that with the rest, and they all work.

User Silouane Gerin
by
3.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.