Question

Find the slope of a line that is through the points (5,-3) and (2, 1). Find the y intercept and then write it in slope intercept form. y= mx + b

Answer 1

Given the points: (5,-3) and (2, 1)

We have that the equation is of the form y = mx + b, where m is the slope and b is the y-intercept. So

- For the slope:

`m=(y2-y1)/(x2-x1)=(1-(-3))/(2-5)=(1+3)/(-3)=-(4)/(3)`

- For the y-intercept:

we use the point (2,1)

`\begin{gathered} y=mx+b \\ 1=-(4)/(3)(2)+b \\ 1=-(8)/(3)+b \\ 1+(8)/(3)=-(8)/(3)+b+(8)/(3) \\ b=(11)/(3) \end{gathered}`

And the equation is:

`y=-(4)/(3)x+(11)/(3)`

Answer:

`y=-(4)/(3)x+(11)/(3)`