Question

Can someone please walk me through these 2 problems? I'm using the formula that the problem states but I have to be going wrong somewhere because all of my answers have been incorrect. The correct answers are below, but I have no idea how to get to them.

35: -13 - 34j volts
37: 28 + 57j volts

Answer 1

`\boxed{35}~~ \begin{cases} I=2-7j\\ Z=4-3j \end{cases}\implies E=(2-7j)(4-3j) \\\\\\ \begin{array}{rllll} 4-3j\\ * ~\hfill 2\\[-0.5em] \hrulefill\\ 8-6j \end{array}~~+ ~~ \begin{array}{rllll} 4-3j\\ * ~\hfill -7j\\[-0.5em] \hrulefill\\ -28j+21j^2 \end{array}\qquad \implies 8-6j-28j+21j^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill E=21j^2-34j+8~\hfill`

`\boxed{36}~~ \begin{cases} I=3+10j\\ Z=6-j \end{cases}\implies E=(3+10j)(6-j) \\\\\\ \begin{array}{rllll} 6-j\\ * ~\hfill 3\\[-0.5em] \hrulefill\\ 18-3j \end{array}~~+ ~~ \begin{array}{rllll} 6-j\\ * ~\hfill 10j\\[-0.5em] \hrulefill\\ 60j-10j^2 \end{array}\qquad \implies 18-3j+60j-10j^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill E=-10j^2+57j+18~\hfill`