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a ball is thrown with a speed of 100 m/s at a height of 150 m take g equals 9.8 m per second calculate the time of flight,angle of projection,range pls help I don't know how to solve it​

User Derek Tomes
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1 Answer

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14 votes

Hi there!

Since the ball is thrown with an initial HORIZONTAL velocity, we can treat this as a free-fall situation since the horizontal motion does NOT impact the ball's vertical motion.

We can use the derived kinematic equation:


t = \sqrt{(2h)/(g)}

Plug in the given values:


t = \sqrt{(2(150))/(9.8)} = \large\boxed{5.53 s}}

The angle of projection is 0° because there is no vertical component to the velocity as the initial velocity is purely horizontal.

Range:

We can use the equation:

dₓ = vₓt

displacement (x direction) = velocity (x direction) · time

Used the solved-for time and given velocity:

dₓ = 100 · 5.53 = 553 m

User Manvel
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