Answer:
The solution is;
![(25)/(24)\text{ or }1(1)/(24)](https://img.qammunity.org/2023/formulas/mathematics/high-school/cz9oj9y2l4t5xokq1v1qvdl7m1pxv70cek.png)
Step-by-step explanation:
We want to evaluate;
![(5)/(6)+(1)/(3)*(5)/(8)](https://img.qammunity.org/2023/formulas/mathematics/high-school/gveonn4py3ruwhd2a5ap6wt2czdt1t72gg.png)
Firstly, we have to evaluate the multiplication;
![\begin{gathered} (5)/(6)+(1)/(3)*(5)/(8) \\ =(5)/(6)+(1*5)/(3*8) \\ =(5)/(6)+(5)/(24) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/sin9k0sxsv96te3lnt9fpa0ruk17l6aona.png)
then we can now evaluate the addition ( According to the Order of BODMAS - Bracket Of Division Multiplication Addition and Subtraction)
![\begin{gathered} (5)/(6)+(5)/(24) \\ =(20+5)/(24) \\ =(25)/(24) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/cgltvkkev5hpcwynw7xknam42ej4c9lu32.png)
Therefore, the solution is;
![(25)/(24)\text{ or }1(1)/(24)](https://img.qammunity.org/2023/formulas/mathematics/high-school/cz9oj9y2l4t5xokq1v1qvdl7m1pxv70cek.png)
i provided the answer in both mixed fraction and improper fraction.