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Mr. Gordon and Mr. O want to race their Tesla's from Englewood Stem to Soldier Field. Soldier Field is approximately 10.5 km away. It takes Mr. O 30 minutes to show up to the stadium. Mr. Gordon arrives 30 minutes after Mr. O. How much faster in (Meters/second) is Mr. O's avg. speed for the race? *

User Kne
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1 Answer

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The distance is the same that was covered.

Distance is speed multiplied by time.

Mr O takes 30 minutes and Mr Gordon takes 1 hour.

So the speed of Mr O is given by:


\text{Speed}=\frac{10.5\operatorname{km}}{1hr}=10.5\operatorname{km}\text{ /hr}

Convert the speed in meter per second.


S_O=10.5*(5)/(18)=(35)/(12)m\text{ /s}

The speed of mr G is:


S_G=(10.5)/(0.5)=21\operatorname{km}\text{ /hr=}(35)/(6)m\text{ /s}

So the difference between the speeds is:


(35)/(6)-(35)/(12)=(35)/(12)=2.9166667\text{ m/s}

So Mr O is 2.9167 m/s faster than Mr Gordon.

User Pierre Ferry
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