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What will be kE of S.H. M when displacement is half of amplitude? ​
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31 votes
31 votes
What will be kE
of S.H. M when displacement is half of amplitude? ​

User Malinchhan
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1 Answer

23 votes
23 votes

Answer:

Potential energy is given as $U = \dfrac{1}{2}k\dfrac{{{x_m}^2}}{4}$ since it's given that amplitude is half of maximum amplitude. Hence the fraction of potential energy to total energy is $0.25$. Hence, the fraction of Kinetic energy to total energy is $0.75$.

Step-by-step explanation:

sorry for wrong :)

User Gduq
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