Question

Question 12, pre calc, I’m at work so I’ll look at it later thanks

Answer 1

Given:

`(14x^2-12x)/(x+6)`

To find the zeros:

Let the numerator be equal to zero

`\begin{gathered} 14x^2-12x=0 \\ 2x\mleft(7x-6\mright)=0 \\ x=0,(6)/(7) \end{gathered}`

Hence, the zeros are,

`((6)/(7),0),(0,0)`