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A right triangle has side lengths 5, 12, and 13 as shown below.Use these lengths to find cos A, tan A, and sinA.cosA=tanA=sinA=

A right triangle has side lengths 5, 12, and 13 as shown below.Use these lengths to-example-1

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r = 13

y = 5

x = 12

cos A = theta (based on the image), then:


\cos \text{ A = }\frac{Adyacent\text{ of A}}{Hypothenus}\text{= }(12)/(13)\text{ }\approx0.92

tan A:


\tan \text{ A =}\frac{Opposite\text{ of A}}{\text{Adyacent of A}}\text{=}(5)/(12)\text{ }\approx\text{ 0}.42

sin A:


\sin \text{ A = }(5)/(13)\text{ }\approx0.38

A right triangle has side lengths 5, 12, and 13 as shown below.Use these lengths to-example-1
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