Question

Line FG is represented by the equation 8x + 3y = 10. Which value is the slope of a line perpendicular to line FG?

Answer 1

writing the equation in the form y = mx +b

`\begin{gathered} 8x+3y=10 \\ 8x-8x+3y=-8x+10 \\ (3y)/(3)=(-8x)/(3)+(10)/(3) \\ y=-(8)/(3)x+(10)/(3) \end{gathered}`

slope is -8/3 and If you multiply the slopes of two perpendicular lines, we get -1, therefore

`-(8)/(3)*(3)/(8)=-1`

value the slope of a line perpendicular to line FG is 3/8