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16 votes
16 votes
W^3 x w^-5
please help and please explain

User KSPR
by
3.1k points

2 Answers

16 votes
16 votes
= W^3+(-5)
= W^3-5
= W^-2
User Lokimidgard
by
2.8k points
8 votes
8 votes

Answer:


\Large \text{$ (1)/(w^2) $}

Explanation:

Given the exponential expression,
\displaytext\mathsf{w^3\:*\:w^(-5)}, where it involves the multiplication of the same base, w, with varying powers.

Using the Product Rule of Exponents, where it states that,
\displaystyle\mathsf{a^(m)\:*\:a^(n)\:=\:a^((m\:+\:n))}.

Hence, we simply need to add the exponents:


\displaytext\mathsf{w^3\:*\:w^(-5)\:=\:w\:^([3\:+\:(-5)])\:=\:w^(-2)}

Next, apply the Negative Exponent Rule, where it states that:
\displaystyle\mathsf{a^(-n)\:=\:(1)/(a^n)}.

Transforming the negative exponent of
\displaytext\mathsf{w^(-2)} becomes a positive exponent by using the Negative Exponent Rule.


\displaytext\mathsf{w^(-2)\:=\:(1)/(w^2)}

User Joe White
by
2.7k points
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