Question

Determine the zeros of the following equation algebraically.x² - 4x - 45=0

Answer 1

Consider the given equation,

`x^2-4x-45=0`

There are 3 methods to solve the equation,

1. Factorization

2. Completing the square

3. Quadratic Formula.

Let us solve the equation using factorization method,

`\begin{gathered} x^2-9x+5x-45=0 \\ x(x-9)+5(x-9)=0 \\ (x-9)(x+5)=0 \\ x-9=0\text{ or }x+5=0 \\ x=9\text{ or }x=-5 \end{gathered}`

Thus, the zeroes of the given quadratic equation are 9 and -5.