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Find the domain 4√x^2 + 3xIndex = 4 & x^2 + 3x under the radical

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Answer:


\text{ Domain: }\lbrack0,\infty)_{}

Step-by-step explanation: Assuming that the Domain contains real values:


D\in\mathfrak{\Re }

In that case, the domain would be:


\begin{gathered} f(x)=4\sqrt[\square]{x^2+3x} \\ \text{ Radical can not be negative:} \\ \therefore\Rightarrow \\ x^2+3x\ge0 \\ x^2\ge3x\Rightarrow x\ge3 \\ \text{ Domain: }\lbrack0,\infty)_{} \end{gathered}

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