360,618 views
35 votes
35 votes
A constant force vector F = (2,8) moves an object along a straight line from the point (2, 5) to the point (13, 10). Find the work done if the distance is measured in feet and the force is measured in pounds.

User Ceco
by
2.7k points

1 Answer

25 votes
25 votes

Answer:

Explanation:

I will ASSUME that the force vector F = 2i + 8j

which has a magnitude of

F = √(2² + 8²) = √68

which has a direction of

θ = arctan (8/2) = 75.96°

The movement has a distance of

d = √((13 - 2)² + (10 - 5)²) = √146 ft

and a direction of

φ = arctan((10 - 5)/(13 - 2)) = 24.44³

the angle between force and motion is

75.96 - 24.44 = 51.52°

Work is the force in the direction of motion times the distance moved.

W = Fd = (√68)(cos51.52)(√146) = 62 J

or we could just break it into components

x direction work = Fd = 2(13 - 2) = 22 J

y direction work = Fd = 8(10 - 5) = 40 J

total work W = 22 + 40 = 62 J

User Akkk
by
2.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.