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Evaluate6! 5!____8! 2!Simple as much as possible

1 Answer

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Step-by-step explanation

If n is a positive integer, n factorial denoted by n! is a product of all positive integers less than or equal to n.


n!=n(n-1)(n-2)\cdot...\cdot(2)(1)

For example:


4!=4\cdot3\cdot2\cdot1=24

In this case, we have:


\begin{gathered} (6!\cdot5!)/(8!\cdot2!)=((6\cdot5\cdot4\cdot3\cdot2\cdot1)(5\cdot4\cdot3\cdot2\cdot1))/((8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1)(2\cdot1)) \\ (6!\cdot5!)/(8!\cdot2!)=(5\cdot4\cdot3)/(8\cdot7) \\ (6!\cdot5!)/(8!\cdot2!)=(5\cdot4\cdot3)/(4\cdot2\cdot7) \\ (6!\cdot5!)/(8!\cdot2!)=(15)/(14) \end{gathered}Answer
(6!\cdot5!)/(8!\cdot2!)=(15)/(14)

User John Slegers
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