Question

Solve the system using elimination 2x+2y=62x-2y=6

Answer 1

Given the system of equations:

`\begin{gathered} 2x+2y=6 \\ 2x-2y=6 \end{gathered}`

we can solve it using elimination by directly adding both equations to get the following:

`\begin{gathered} 2x+2y=6 \\ 2x-2y=6 \\ ---------- \\ 4x=12 \\ \Rightarrow x=(12)/(4)=3 \\ x=3 \end{gathered}`

now that we have that x=3, we can find y using this value on any of the two equations:

`\begin{gathered} 2x+2y=6 \\ x=3 \\ \Rightarrow2(3)+2y=6 \\ \Rightarrow6+2y=6 \\ \Rightarrow2y=6-6=0 \\ \Rightarrow2y=0 \\ y=0 \end{gathered}`

therefore, the solution of the system is (3,0)