The formula to calculate the amount of a value that is subject to a compounded interest is shown below:
![A=P\cdot(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/college/1hp3okcapx09i2vvtx1r7b88nlkj70kqsm.png)
Where A is the final amount, P is the principal invested, r is the annual interest rate, n is the times it get compounded in a year and t is the elapsed time.
When we need to compound an amount quarterly, it will be compounded 4 times in a year, therefore n is equal to 4.
![\begin{gathered} A=2000\cdot(1+(0.07)/(4))^(4\cdot6) \\ A=2000\cdot(1+0.0175)^(24) \\ A=2000\cdot(1.0175)^(24) \\ A=2000\cdot1.5164=3032.8 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3u1bu3hse5t3cgxoyxmmkqs6ga3i4cy0m8.png)
When we need to compound it monthly, it will be compounded 12 times in a year, therefore n is equal to 12.
![\begin{gathered} A=2000\cdot(1+(0.07)/(12))^(12\cdot6) \\ A=2000\cdot(1.00583)^(72) \\ A=2000\cdot1.51974=3039.48 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gg05xymnda90ms3z36bwvv93pdi2tqitew.png)
When we need to compound it continuously the formula will change to the one shown below:
![A=P\cdot e^(rt)](https://img.qammunity.org/2023/formulas/mathematics/college/q1bg6j6dv8d1o1ne07djv6jjj1slppwjzw.png)
Applying the data we have:
![\begin{gathered} A=2000\cdot e^(0.07\cdot6) \\ A=2000\cdot e^(0.42) \\ A=2000\cdot1.52196 \\ A=3043.92 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ijwv98mul9ekg4li47lnjyv2wbb2x3ba0w.png)