We want to find the width of the enlargement, where its length is 40 inches, and the original size is 20 inches wide and 25 inches tall.
We can state a proportion, calling by x the width of the enlargement, and we get:
![(20)/(25)=(x)/(40)](https://img.qammunity.org/2023/formulas/mathematics/college/2ou7nucpckfhq6mxvp5vcfzf2pwt72dk4v.png)
We multiply means and extremes:
![\begin{gathered} 20\cdot40=25\cdot x \\ 800=25\cdot x \\ \text{And we solve for x:} \\ x=(800)/(25)=32 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cxndc5b87rder3x2r5ck6cfougk1n5njzz.png)
This means that the width of the enlargement 32 inches.