I was in the last three evenings Jessica received a total of 126 phone calls at the call center the first evening she receives six more calls than the second evening the third evening she received three times as many phone calls is the second how many phone calls did she receive each evening
Let
x -----> number of calls in the first evening
y -----> number of calls in the secobnd evening
z -----> number of calls in the third evening
we know that
x+y+z=126 --------> equation A
x=y+6 ------> equation B
z=3y ------> equation C
substitute equation B and equation C in equation A
(y+6)+y+(3y)=126
solve for y
5y+6=126
5y=120
y=24
Find the value of x
x=y+6
x=24+6
x=30
Find the value of z
z=3y
z=3(24)
z=72
therefore
30 calls in the first evening
24 calls in the second evening
72 calls in the third evening