Question

Solve the system using the substitution technique:There is no solution.

Answer 1

Given

The system of equations,

`\begin{gathered} x-0.2y=1\text{ \_\_\_\_\_\_}(1) \\ -10x+2y=5\text{ \_\_\_\_\_\_}(2) \end{gathered}`

To find the solution.

Step-by-step explanation:

It is given that,

`\begin{gathered} x-0.2y=1\text{ \_\_\_\_\_\_}(1) \\ -10x+2y=5\text{ \_\_\_\_\_\_}(2) \end{gathered}`

That implies,

`(1)\Rightarrow x=1+0.2y`

Substitute the value of x in (2).

Then,

`\begin{gathered} -10x+2y=5 \\ -10(1+0.2y)+2y=5 \\ -10-2y+2y=5 \\ -10=5\text{ }(it\text{ }is\text{ }not\text{ }possible) \end{gathered}`

Hence, there is no solution.