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Calculate the number of atoms contained in 0.68 moles of Al (CN)3

User Memo
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1 Answer

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4.094*10^23 moles of Al(CN)3

1 mole = 6.022*10^23 atoms

0.68 moles = x atoms

x = 4.094*10^23 atoms of Al(CN)3

User Marcus Johansson
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