We are given the following two functions
![\begin{gathered} f(x)=x^2 \\ g(x)=(-x)^2-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/s8ma2famumrdm3mhegjhj8l9zs9othmifu.png)
Recall that the rule for reflection over the y-axis is given by
![f(x)\rightarrow f(-x)](https://img.qammunity.org/2023/formulas/mathematics/college/3czoazwsy144kd7ey1sp5qdzqkyofip8tp.png)
As you can see, the graph of g(x) will be a reflection over the y-axis of the graph f(x).
Recall that the rule for vertical translation (upward) is given by
![f(x)\rightarrow f(x)-d](https://img.qammunity.org/2023/formulas/mathematics/college/fmesw2g0090olrly6oxnb7ek4dcwlho9ph.png)
The above translation will shift the graph vertically upward by d units.
For the given case, d = 1
As you can see, the graph of g(x) will be a vertical translation of the graph f(x)
Therefore, we can conclude that the graph of g(x) will be a reflection over the y-axis and a vertical translation of the graph f(x).
1st option is the correct answer.