Question

What is an equation of the line that passes through the point (8,-8) and is perpendicular to the line 4x-3y=18

Answer 1

Explanation:

4x-3y=18

3y=4x-18

y=4/3x-6

By y=mx+c , Slope of line 4x-3y=18 is 4/3

Since the required line is perpendicular to the line 4x-3y=18 ,

slope of required line * Slope of line 4x-3y=18 = -1

slope of required line = -1/(4/3) = -3/4

Since the required line passes through (8,-8)

By point-slope form,

y-(-8)= -3/4(x-8)

y= -3/4x-2