Question

What is the remainder when the sum of the first five primes is divided by the sixth prime?

Answer 1

To determine the sum of first five primes divided by the sixth:

The first prime numbers are 2 , 3 , 5 , 7 , 11

`\text{Sum of the first five prime = 2+3+5+7+11=28}`

The sixth prime number = 13

`\begin{gathered} \text{dividing the sum of the first five number by the sixth} \\ 2+3+5+7+11=28 \\ \frac{\text{first five prime}}{sixth}=(28)/(13)=2\text{ remainder 2} \end{gathered}`

Therefore the remainder = 2