Question

I need help with my math

Answer 1

Given

Graph

Procedure

`\begin{gathered} 3x+2y=-6 \\ 2y=-6-3x \\ y=(-3x-6)/(2) \\ y=-(3)/(2)x-3 \\ \end{gathered}`

`\begin{gathered} 3y=2x+15 \\ y=(2x+15)/(3) \\ y=(2)/(3)x+(15)/(3) \\ y=(2)/(3)x+5 \\ \end{gathered}`

`\begin{gathered} y-4x=8 \\ y=4x+8 \end{gathered}`

`\begin{gathered} y-8=-(1)/(2)(x+4) \\ y-8=-(1)/(2)x-(1)/(2)4 \\ y=-(1)/(2)x-2+8 \\ y=-(1)/(2)x+6 \end{gathered}`

`\begin{gathered} 3x-4y=8 \\ 4y=-8+3x \\ y=(3x-8)/(4) \\ y=(3)/(4)x-(8)/(4) \\ y=(3)/(4)x-2 \end{gathered}`

`\begin{gathered} 6x-2y=10 \\ 2y=6x-10 \\ y=(6x-10)/(2) \\ y=(6x)/(2)-(10)/(2) \\ y=3x-5 \end{gathered}`