Question

2. A train travels a distance of 30 km with a uniform speed of 54 km/h.It travels another distance of 50 km with a uniform speed of 90 km/h.Calculate the average speed of the train.

Answer 1

The average speed is defined as:

`v=(d)/(t)`

Then for the first 30 km it took:

`t=(30)/(54)=0.556`

hours.

The second distance of 50 km took:

`t=(50)/(90)=0.556`

Therefore the average speed is:

`v=(30+50)/(0.556+0.556)=72`

72 km/h.