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A 500 watt heater carries a current of 4 A. What is the resistance of the heating element?Group of answer choices85.7 Ω42.8 Ω31.3 Ω11.2 Ω

User Jtalarico
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1 Answer

4 votes

ANSWER

31.3 Ω

Step-by-step explanation

Given:

• The power of the heating device, P = 500 W

,

• The current, I = 4 A

Unknown:

• The resistance of the heating device, R

The power, P, on a resistance R when a current I flows through it is,


P=I^2\cdot R

Solving for R,


R=(P)/(I^2)

Replace with the known values,


R=(500W)/(4^2A^2)=31.25\Omega\approx31.3\Omega

Hence, the resistance of the heating device is 31.3 Ω.

User Aftab Ansari
by
8.6k points
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