Question

Determine the magnitude and direction of vector a = (3,8) Round to the nearest tenths. |a| =theta =

Answer 1

Recall the definitions of the magnitude and direction of a vector:

`\begin{gathered} \parallel a\parallel=\sqrt[]{3^2+8^2}=\sqrt[]{73}=8.5 \\ \theta=\tan ^(-1)((8)/(3))=69.4^(\circ) \end{gathered}`