Question

Find an equation for the line below A(-2,2) B(6,-4)

Answer 1

Given:

The line passes through point (-2,2) and (6,-4).

Step-by-step explanation:

The equation of line passing through points (x_1,y_1) and (x_2,y_2) is,

`y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)`

Determine the equation of line passing through points (-2,2) and (6,-4).

`\begin{gathered} y-2=(-4-2)/(6-(-2))(x-(-2)) \\ y-2=(-6)/(8)(x+2) \\ y-2=-(3)/(4)x-(3)/(4)\cdot2 \\ y=-(3)/(4)x-(3)/(2)+2 \\ =-(3)/(4)x+(1)/(2) \end{gathered}`

So equation of line is y = -3/4x + 1/2.